During the same constant acceleration of 3.0 m/s^2 from rest, what is the velocity after 2.0 s?

Prepare for the MIAT Physics Test with our comprehensive quizzes. Use multiple choice questions and review explanations for each answer. Get ready to excel in your exam!

Multiple Choice

During the same constant acceleration of 3.0 m/s^2 from rest, what is the velocity after 2.0 s?

Explanation:
When acceleration is constant, velocity changes linearly with time: v = v0 + a t. Starting from rest means v0 = 0, so v = a t. With a = 3.0 m/s^2 and t = 2.0 s, v = 3.0 × 2.0 = 6.0 m/s. The direction is the same as the acceleration, and the units (m/s) come from m/s^2 times seconds. So the velocity after 2 seconds is 6 m/s.

When acceleration is constant, velocity changes linearly with time: v = v0 + a t. Starting from rest means v0 = 0, so v = a t. With a = 3.0 m/s^2 and t = 2.0 s, v = 3.0 × 2.0 = 6.0 m/s. The direction is the same as the acceleration, and the units (m/s) come from m/s^2 times seconds. So the velocity after 2 seconds is 6 m/s.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy