A liquid density 46.8 lb/ft^3; compute SG.

A liquid density 46.8 lb/ft^3; compute SG.

• A. 0.73
• B. 0.70
• C. 0.75
• D. 0.77

Answer: (C)

Specific gravity is the ratio of a liquid’s density to the density of water, using consistent units. In English engineering units, water’s density is about 62.4 lb/ft^3. So SG = 46.8 / 62.4 = 0.75. Since the liquid is lighter than water, the SG is less than 1, which matches the given value. The other options would require different densities for the liquid (e.g., 0.73 would imply 45.5 lb/ft^3, etc.), so 0.75 is the correct result.

Specific gravity is the ratio of a liquid’s density to the density of water, using consistent units. In English engineering units, water’s density is about 62.4 lb/ft^3. So SG = 46.8 / 62.4 = 0.75. Since the liquid is lighter than water, the SG is less than 1, which matches the given value. The other options would require different densities for the liquid (e.g., 0.73 would imply 45.5 lb/ft^3, etc.), so 0.75 is the correct result.