A capacitor with C = 20 μF is charged to V = 10 V. What is the energy stored?

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Multiple Choice

A capacitor with C = 20 μF is charged to V = 10 V. What is the energy stored?

Explanation:
A capacitor stores energy according to E = (1/2) C V^2. Convert the capacitance to farads: 20 μF = 20 × 10^-6 F = 2.0 × 10^-5 F. With V = 10 V, E = 0.5 × (2.0 × 10^-5) × (10)^2 = 0.5 × 2.0 × 10^-5 × 100 = 1.0 × 10^-3 J. So the energy stored is 1.0 × 10^-3 J (1 millijoule).

A capacitor stores energy according to E = (1/2) C V^2. Convert the capacitance to farads: 20 μF = 20 × 10^-6 F = 2.0 × 10^-5 F. With V = 10 V, E = 0.5 × (2.0 × 10^-5) × (10)^2 = 0.5 × 2.0 × 10^-5 × 100 = 1.0 × 10^-3 J. So the energy stored is 1.0 × 10^-3 J (1 millijoule).

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